Integration along fibers

In differential geometry, the integration along fibers of a k-form yields a ( k m ) {\displaystyle (k-m)} -form where m is the dimension of the fiber, via "integration". It is also called the fiber integration.

Definition

Let π : E B {\displaystyle \pi :E\to B} be a fiber bundle over a manifold with compact oriented fibers. If α {\displaystyle \alpha } is a k-form on E, then for tangent vectors wi's at b, let

( π α ) b ( w 1 , , w k m ) = π 1 ( b ) β {\displaystyle (\pi _{*}\alpha )_{b}(w_{1},\dots ,w_{k-m})=\int _{\pi ^{-1}(b)}\beta }

where β {\displaystyle \beta } is the induced top-form on the fiber π 1 ( b ) {\displaystyle \pi ^{-1}(b)} ; i.e., an m {\displaystyle m} -form given by: with w i ~ {\displaystyle {\widetilde {w_{i}}}} lifts of w i {\displaystyle w_{i}} to E {\displaystyle E} ,

β ( v 1 , , v m ) = α ( v 1 , , v m , w 1 ~ , , w k m ~ ) . {\displaystyle \beta (v_{1},\dots ,v_{m})=\alpha (v_{1},\dots ,v_{m},{\widetilde {w_{1}}},\dots ,{\widetilde {w_{k-m}}}).}

(To see b ( π α ) b {\displaystyle b\mapsto (\pi _{*}\alpha )_{b}} is smooth, work it out in coordinates; cf. an example below.)

Then π {\displaystyle \pi _{*}} is a linear map Ω k ( E ) Ω k m ( B ) {\displaystyle \Omega ^{k}(E)\to \Omega ^{k-m}(B)} . By Stokes' formula, if the fibers have no boundaries(i.e. [ d , ] = 0 {\displaystyle [d,\int ]=0} ), the map descends to de Rham cohomology:

π : H k ( E ; R ) H k m ( B ; R ) . {\displaystyle \pi _{*}:\operatorname {H} ^{k}(E;\mathbb {R} )\to \operatorname {H} ^{k-m}(B;\mathbb {R} ).}

This is also called the fiber integration.

Now, suppose π {\displaystyle \pi } is a sphere bundle; i.e., the typical fiber is a sphere. Then there is an exact sequence 0 K Ω ( E ) π Ω ( B ) 0 {\displaystyle 0\to K\to \Omega ^{*}(E){\overset {\pi _{*}}{\to }}\Omega ^{*}(B)\to 0} , K the kernel, which leads to a long exact sequence, dropping the coefficient R {\displaystyle \mathbb {R} } and using H k ( B ) H k + m ( K ) {\displaystyle \operatorname {H} ^{k}(B)\simeq \operatorname {H} ^{k+m}(K)} :

H k ( B ) δ H k + m + 1 ( B ) π H k + m + 1 ( E ) π H k + 1 ( B ) {\displaystyle \cdots \rightarrow \operatorname {H} ^{k}(B){\overset {\delta }{\to }}\operatorname {H} ^{k+m+1}(B){\overset {\pi ^{*}}{\rightarrow }}\operatorname {H} ^{k+m+1}(E){\overset {\pi _{*}}{\rightarrow }}\operatorname {H} ^{k+1}(B)\rightarrow \cdots } ,

called the Gysin sequence.

Example

Let π : M × [ 0 , 1 ] M {\displaystyle \pi :M\times [0,1]\to M} be an obvious projection. First assume M = R n {\displaystyle M=\mathbb {R} ^{n}} with coordinates x j {\displaystyle x_{j}} and consider a k-form:

α = f d x i 1 d x i k + g d t d x j 1 d x j k 1 . {\displaystyle \alpha =f\,dx_{i_{1}}\wedge \dots \wedge dx_{i_{k}}+g\,dt\wedge dx_{j_{1}}\wedge \dots \wedge dx_{j_{k-1}}.}

Then, at each point in M,

π ( α ) = π ( g d t d x j 1 d x j k 1 ) = ( 0 1 g ( , t ) d t ) d x j 1 d x j k 1 . {\displaystyle \pi _{*}(\alpha )=\pi _{*}(g\,dt\wedge dx_{j_{1}}\wedge \dots \wedge dx_{j_{k-1}})=\left(\int _{0}^{1}g(\cdot ,t)\,dt\right)\,{dx_{j_{1}}\wedge \dots \wedge dx_{j_{k-1}}}.} [1]

From this local calculation, the next formula follows easily (see Poincaré_lemma#Direct_proof): if α {\displaystyle \alpha } is any k-form on M × [ 0 , 1 ] , {\displaystyle M\times [0,1],}

π ( d α ) = α 1 α 0 d π ( α ) {\displaystyle \pi _{*}(d\alpha )=\alpha _{1}-\alpha _{0}-d\pi _{*}(\alpha )}

where α i {\displaystyle \alpha _{i}} is the restriction of α {\displaystyle \alpha } to M × { i } {\displaystyle M\times \{i\}} .

As an application of this formula, let f : M × [ 0 , 1 ] N {\displaystyle f:M\times [0,1]\to N} be a smooth map (thought of as a homotopy). Then the composition h = π f {\displaystyle h=\pi _{*}\circ f^{*}} is a homotopy operator (also called a chain homotopy):

d h + h d = f 1 f 0 : Ω k ( N ) Ω k ( M ) , {\displaystyle d\circ h+h\circ d=f_{1}^{*}-f_{0}^{*}:\Omega ^{k}(N)\to \Omega ^{k}(M),}

which implies f 1 , f 0 {\displaystyle f_{1},f_{0}} induce the same map on cohomology, the fact known as the homotopy invariance of de Rham cohomology. As a corollary, for example, let U be an open ball in Rn with center at the origin and let f t : U U , x t x {\displaystyle f_{t}:U\to U,x\mapsto tx} . Then H k ( U ; R ) = H k ( p t ; R ) {\displaystyle \operatorname {H} ^{k}(U;\mathbb {R} )=\operatorname {H} ^{k}(pt;\mathbb {R} )} , the fact known as the Poincaré lemma.

Projection formula

Given a vector bundle π : EB over a manifold, we say a differential form α on E has vertical-compact support if the restriction α | π 1 ( b ) {\displaystyle \alpha |_{\pi ^{-1}(b)}} has compact support for each b in B. We write Ω v c ( E ) {\displaystyle \Omega _{vc}^{*}(E)} for the vector space of differential forms on E with vertical-compact support. If E is oriented as a vector bundle, exactly as before, we can define the integration along the fiber:

π : Ω v c ( E ) Ω ( B ) . {\displaystyle \pi _{*}:\Omega _{vc}^{*}(E)\to \Omega ^{*}(B).}

The following is known as the projection formula.[2] We make Ω v c ( E ) {\displaystyle \Omega _{vc}^{*}(E)} a right Ω ( B ) {\displaystyle \Omega ^{*}(B)} -module by setting α β = α π β {\displaystyle \alpha \cdot \beta =\alpha \wedge \pi ^{*}\beta } .

Proposition — Let π : E B {\displaystyle \pi :E\to B} be an oriented vector bundle over a manifold and π {\displaystyle \pi _{*}} the integration along the fiber. Then

  1. π {\displaystyle \pi _{*}} is Ω ( B ) {\displaystyle \Omega ^{*}(B)} -linear; i.e., for any form β on B and any form α on E with vertical-compact support,
    π ( α π β ) = π α β . {\displaystyle \pi _{*}(\alpha \wedge \pi ^{*}\beta )=\pi _{*}\alpha \wedge \beta .}
  2. If B is oriented as a manifold, then for any form α on E with vertical compact support and any form β on B with compact support,
    E α π β = B π α β {\displaystyle \int _{E}\alpha \wedge \pi ^{*}\beta =\int _{B}\pi _{*}\alpha \wedge \beta } .

Proof: 1. Since the assertion is local, we can assume π is trivial: i.e., π : E = B × R n B {\displaystyle \pi :E=B\times \mathbb {R} ^{n}\to B} is a projection. Let t j {\displaystyle t_{j}} be the coordinates on the fiber. If α = g d t 1 d t n π η {\displaystyle \alpha =g\,dt_{1}\wedge \cdots \wedge dt_{n}\wedge \pi ^{*}\eta } , then, since π {\displaystyle \pi ^{*}} is a ring homomorphism,

π ( α π β ) = ( R n g ( , t 1 , , t n ) d t 1 d t n ) η β = π ( α ) β . {\displaystyle \pi _{*}(\alpha \wedge \pi ^{*}\beta )=\left(\int _{\mathbb {R} ^{n}}g(\cdot ,t_{1},\dots ,t_{n})dt_{1}\dots dt_{n}\right)\eta \wedge \beta =\pi _{*}(\alpha )\wedge \beta .}

Similarly, both sides are zero if α does not contain dt. The proof of 2. is similar. {\displaystyle \square }

See also

  • Transgression map

Notes

  1. ^ If α = g d t d x j 1 d x j k 1 {\displaystyle \alpha =g\,dt\wedge dx_{j_{1}}\wedge \cdots \wedge dx_{j_{k-1}}} , then, at a point b of M, identifying x j {\displaystyle \partial _{x_{j}}} 's with their lifts, we have:
    β ( t ) = α ( t , x j 1 , , x j k 1 ) = g ( b , t ) {\displaystyle \beta (\partial _{t})=\alpha (\partial _{t},\partial _{x_{j_{1}}},\dots ,\partial _{x_{j_{k-1}}})=g(b,t)}
    and so
    π ( α ) b ( x j 1 , , x j k 1 ) = [ 0 , 1 ] β = 0 1 g ( b , t ) d t . {\displaystyle \pi _{*}(\alpha )_{b}(\partial _{x_{j_{1}}},\dots ,\partial _{x_{j_{k-1}}})=\int _{[0,1]}\beta =\int _{0}^{1}g(b,t)\,dt.}
    Hence, π ( α ) b = ( 0 1 g ( b , t ) d t ) d x j 1 d x j k 1 . {\displaystyle \pi _{*}(\alpha )_{b}=\left(\int _{0}^{1}g(b,t)\,dt\right)dx_{j_{1}}\wedge \cdots \wedge dx_{j_{k-1}}.} By the same computation, π ( α ) = 0 {\displaystyle \pi _{*}(\alpha )=0} if dt does not appear in α.
  2. ^ Bott & Tu 1982, Proposition 6.15.; note they use a different definition than the one here, resulting in change in sign.

References

  • Michele Audin, Torus actions on symplectic manifolds, Birkhauser, 2004
  • Bott, Raoul; Tu, Loring (1982), Differential Forms in Algebraic Topology, New York: Springer, ISBN 0-387-90613-4